m为何值时颠末两点A(m？

kAB=(2m-1-2)/(-m-m)=(2m-3)/(-2m)=tan60°=√3

(2m-3)/(-2m)=√3

2m-3=-2√3m

(2+2√3)m=3

m=3/(2+2√3)

m=3(√3-1)/4