500条左右的计算机语言程序

  3。1 main( )

int x;

printf(“please input x=”);

scanf(“%d”,&x);

if(!(x%2))printf(“\n%d is a oushu “,x);

else printf(“\n%d is a jishu “,x);

3。

  2

main()

int a,b,c,t;

printf(“please input a,b,c=”);

scanf(“%d,%d,%d”,&a,&b,&c);

if(ab)max=a; /*能够利用前提表达式来完成max=(a>b?a,b)>c? (a>b?a,b):c;*/

else max=b;

if(max-10&&x0&&x=10)printf(“\n x=%d,do nothing”,x);

else printf(“ y=%d”,y);

(2)main( )

{int x,y;

printf(“please input x=”);

scanf(“%d”,&x);

if(x>-10&&x=10)printf(“\n x=%d,do nothing”,x);

else if(x0) printf(“\n x=%d,y=2*x+1=%d”,x,2*x+1);

else ; /*那个语句能够省略，因为它是一个空语句，什么也不做*/

if(x0) printf(“\n x=%d,y=2*x+1=%d”,x,2*x+1);

else printf(“\n x=%d,do nothing”,x);

3。

  6 a=3,b=4,c=5

(1) a+b>c&&b==c

(2) a||b+c&&b-c

(3) !(a>b)&&!c||1

(4) !(x=a)&&(y=b)&&0

(5) !(a+b)+c-1&&b+c/2

谜底：0,1,1,0,1

3。

  7

(1) a+b>c&&b+c>a&&c+a>b , abs(a-b)=’a’&&ch=’A’&&chc&&b+c>a&&c+a>b)

{ k=(a+b+c)/2。0;

mianji=sqrt(k*fabs(k-a)*fabs(k-b)*fabs(k-c));

printf(“mianji=%f”,mianji);

else printf(“a,b,c can’t make a sanjiaoxing “);

3。

  9

main()

{int x;

printf(“please input x=);

scanf(“%d”,&x);

switch(x%7)

{ case 0 :printf(“\n日曜日”);break;

case1 :printf(“\n礼拜一”); break;

case 2 :printf(“\n礼拜二”); break;

case 3 :printf(“\n礼拜三”); break;

case 4 :printf(“\n木曜日”); break;

case 5 :printf(“\n礼拜五”); break;

case 6 :printf(“\n礼拜六”);

3．10

(1) main()

{ int x,y;

printf(“plese input x,y=”);

scanf(“%d,%d”,&x,&y);

if(x>0&&y>0)printf(“x,y is in I xiangxian”);

if(x0)printf(“x,y is in II xiangxian”);

if(x0&&y0)

if(y>0) printf(“x,y is in I xiangxian”);

else printf(“x,y is in IV xiangxian”);

else

if(y>0) printf(“x,y is in II xiangxian”);

else printf(“x,y is in III xiangxian”);

else printf(“x,y is in 0 xiangxian”);

(7) main()

{int x,y;

printf(“plese input x,y=”);

scanf(“%d,%d”,&x,&y);

if(x>0&&y>0)printf(“x,y is in I xiangxian”);

else if(x0)printf(“x,y is in II xiangxian”);

else if(x0&&y